If the voltage peaks from the rectifier were not continually charging up the capacitor, it would eventually discharge and the output voltage would decrease all the way down to 0V. The discharging that does occur between peaks gives rise to a small 'ripple' voltage. The amount of ripple is affected by a combination of three factors:
- The value of the capacitor. The larger the capacitor value, the more charge it can store, and the slower it will discharge. Therefore, smoothing capacitors are normally electrolytic capacitors with values over 470μF.
- The amount of current used by the circuit. If the circuit connected to the power supply takes a lot of current, the capacitor will discharge more quickly and there will be a higher ripple voltage.
- The frequency of the peaks. The more frequent the voltage peaks from the rectifier, the more often the capacitor will be charged, and the lower the ripple voltage will be.
If you want to calculate the ripple voltage, you can use this formula...
...where Vr is the ripple voltage in Volts, I is the current taken by the circuit in Amps, C is the value of the smoothing capacitor in Farads, and F is the frequency of the peaks from the full-wave rectifier, in Hertz. This frequency will be double the normal mains frequency, i.e. 100Hz in the case of the UK mains supply, or 120Hz in the case of the US mains supply.
The ripple voltage should not be more than 10% of Vs - if it is, increase the value of the smoothing capacitor.
Lots of circuits will work fine from a smoothed power supply, but some must have a completely regular supply with no ripple voltage. The next article in this series discusses regulators which can provide this regular power supply.
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